2x^2+10-28/4x+28

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Solution for 2x^2+10-28/4x+28 equation: 


x in (-oo:+oo)

2*x^2-((28/4)*x)+10+28 = 0

2*x^2-7*x+10+28 = 0

2*x^2-7*x+38 = 0

DELTA = (-7)^2-(2*4*38)

DELTA = -255

DELTA < 0

x belongs to the empty set

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